# List of combinations from a list of lists in Groovy

Groovy has many useful functions built-in, and one of them is `Iterable.combinations()`

that takes aggregated collections and finds all combinations of items. However, if we take a look its source code, we will find out that it was implemented using very imperative approach (nested for-loops + some if-statement). In this blog post I will show you how to implement the same function using Groovy and tail-recursion algorithm. Enjoy!

## An example

Before we jump into a recursive algorithm implementation, let’s take a look at some examples in Groovy Shell.

`combinations()`

function executed in groovysh```
groovy:000> [[]].combinations()
===> []
groovy:000> [['a']].combinations()
===> [[a]]
groovy:000> [['a',1],['b',2],[3,4,5]].combinations()
===> [[a, b, 3], [1, b, 3], [a, 2, 3], [1, 2, 3], [a, b, 4], [1, b, 4], [a, 2, 4], [1, 2, 4], [a, b, 5], [1, b, 5], [a, 2, 5], [1, 2, 5]]
```

## Tail-recursive algorithm

Without further ado, let’s implement a recursive function that takes advantage of a tail call. Our algorithm can be described in just a few steps:

If the input collection is empty, return accumulated result (stop condition).

Take the head of the input collection and create n new variants of each list collected in the accumulator by appending elements taken from the head list.

Call the function recursively with the tail of the input collection and re-evaluated accumulator.

We know the algorithm, let’s write some code.

`combinations(list)`

function```
import groovy.transform.CompileStatic
import groovy.transform.TailRecursive
/**
* Generates combinations of elements.
*
* Example:
* combinations([['a',1], ['b',2], [10,20]]) == [['a','b',10],['a','b',20],['a',2,10],['a',2,20],[1,'b',10],[1,'b',20],[1,2,10],[1,2,20]]
*
*/
@TailRecursive
@CompileStatic
<T> List<List<T>> combinations(final List<List<T>> xss, final List<List<T>> result = [[]]) {
return !xss ? result : combinations(xss.tail(), process(xss.head(), result))
}
/**
* Generates a new accumulator by creating `n` new variants for each
* accumulated list by appending elements taken from head list (`xs`).
*
* Example:
* acc = [[]], xs = [1,2,3] => [[1],[2],[3]]
* acc = [[1],[2],[3]], xs = [4,5] => [[1,4],[1,5],[2,4],[2,5],[3,4],[3,5]]
* acc = [[1,4],[1,5],[2,4],[2,5],[3,4],[3,5]], xs = ['a','b'] => [[1,4,'a'],[1,4,'b'],[1,5,'a'],[1,5,'b], ..., [3,5,'a'],[3,5,'b']]
* ...
*/
@CompileStatic
<T> List<List<T>> process(final List<T> xs, final List<List<T>> acc) {
return acc.inject([]) { yss, ys -> yss + xs.collect { x -> ys + x } }
}
// Let's see if implemented function meets expectations
def values = [[1,2,3],[4,5],[6,7,8,9]]
def expected = [[1,4,6],[1,4,7],[1,4,8],[1,4,9],[1,5,6],[1,5,7],[1,5,8],[1,5,9],[2,4,6],[2,4,7],[2,4,8],[2,4,9],[2,5,6],[2,5,7],[2,5,8],[2,5,9],[3,4,6],[3,4,7],[3,4,8],[3,4,9],[3,5,6],[3,5,7],[3,5,8],[3,5,9]]
assert combinations(values) == expected
// Let's see if combinations(list) produces the same output as list.combinations()
def list = [['a',1], ['b',2], [10,20]]
assert (list.combinations()) as Set == (combinations(list) as Set)
```

I made this exemplary code quite verbose, but you can see that after removing the verbosity it could be a one-liner.

## Bonus: Haskell implementation

The recursive algorithm we have implemented using Groovy asks for an example in a functional language. Let’s see what could the implementation of combinations function look like in Haskell.

```
combinations :: [[a]] -> [[a]]
combinations [] = [[]]
combinations (xs:xss) = [x : xs' | x <- xs, xs' <- combinations xss]
```

It’s even more concise and more straightforward - just as expected.

```
*Prelude> combinations [[1,2],[3,4],[5,6]]
[[1,3,5],[1,3,6],[1,4,5],[1,4,6],[2,3,5],[2,3,6],[2,4,5],[2,4,6]]
*Prelude> combinations [['a','b'], ['c'], ['d','e','f']]
["acd","ace","acf","bcd","bce","bcf"]
*Prelude> combinations []
[[]]
```

If you like learning new programming languages or exploring and mastering the one you already know by solving exciting puzzles, there is an excellent opportunity to do so - Advent Of Code 2018 starts on Saturday, December 1st. It is 25 days of programming simple solutions to quite challenging problems. You can’t miss it! |

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